ABYC E-11 Marine Ampacity Calculator
Enter circuit current, one-way run length, system voltage, conductor temperature rating, location, bundle count, and allowable voltage drop. Returns the minimum AWG sized to ABYC E-11 ampacity tables and the 3% / 10% voltage-drop rule, whichever requires more copper.
Marine Toolkit runs this math past cell range
Worked example
30 A panel feed, 25 ft one-way run on a 12 V DC boat, 3 % drop allowed, 75 °C tinned copper, general (non-engine-room) location, single conductor.
Sources
Common mistakes
- Using NEC ampacity tables on a boat. NEC residential values undersize for the marine environment — vibration, salt, and engine-room heat all derate copper. Always use ABYC E-11 Tables V/VI/VII.
- Forgetting round-trip length. The voltage-drop formula uses 2× one-way length because current returns on the negative conductor (DC) or neutral (AC). A 25 ft run is 50 ft of copper.
- Ignoring connector and terminal drop. Each crimped lug on a battery cable adds roughly 0.1 V at full load. On a 12 V starter circuit with four crimps, that's 3 % gone before the wire even contributes.
FAQ
Why does ABYC require larger wire than NEC for the same load?
The marine environment derates conductor ampacity per ABYC E-11 §10.4 (ambient compensation). Vibration, salt corrosion, and engine-room heat all reduce safe current capacity, so ABYC tables run more conservative than NEC residential values. A circuit that's fine in a dry wall cavity can overheat in a bilge or behind an engine cover.
Single-conductor vs sheathed cable ampacity?
ABYC Table V (single conductor in free air) gives the highest ampacity. Table VI (2-3 conductor sheathed) is lower, and Table VII (4+ conductors bundled) lower still. Bundling derates because heat from each conductor can't radiate away — the inner cores cook the outer ones. Always count every current-carrying conductor that shares a sheath or wire loom.
12 V vs 24 V system — does wire size differ?
Yes. Halving the voltage doubles the current for the same power (P = V × I). Voltage drop scales linearly with current, so a 12 V boat needs roughly 2× the copper of a 24 V boat at the same load and run length. This is why long bow-thruster runs and inverter feeds often drive a 24 V house bank decision on larger vessels.
Where does the K = 10.75 come from?
It's the resistivity of copper at 75 °C expressed in circular-mil units: ρ ≈ 10.75 Ω·CM/ft. The constant lets you compute voltage drop directly from current, length, and conductor cross-section in CM: Vd = K × I × 2L / CM. Aluminum (rare in marine) uses K ≈ 17.
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Related
CalcSpec is an estimator for qualified marine technicians, electricians, and surveyors. Results do not replace ABYC certification, USCG inspection, or a licensed marine electrician's judgment. Always verify against the current edition of ABYC E-11 and applicable USCG regulations.